(2x-3)^5/(7x^2-2)

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Solution for (2x-3)^5/(7x^2-2) equation: 


D( x )

7*x^2-2 = 0

7*x^2-2 = 0

7*x^2-2 = 0

7*x^2 = 2 // : 7

x^2 = 2/7

x^2 = 2/7 // ^ 1/2

abs(x) = (2/7)^(1/2)

x = (2/7)^(1/2) or x = -(2/7)^(1/2)

x in (-oo:-(2/7)^(1/2)) U (-(2/7)^(1/2):(2/7)^(1/2)) U ((2/7)^(1/2):+oo)

((2*x-3)^5)/(7*x^2-2) = 0

2*x-3 = 0 // + 3

2*x = 3 // : 2

x = 3/2

x in { 3/2, 3/2, 3/2, 3/2, 3/2 }

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